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Category: Chemistry
Explain why the equivalent weight of H2​SO4​is half the molar mass of this substance. How many hydrogen ions does each H2​SO4​ molecule produce when reacting with an excess of OH−ions?
Coursepivot December 14, 2022 17:03
Explanation 1 Answer The mass of an acid that can contain 1 mol H+ ions in an aqueous solution is known as its equivalent weight. In an aqueous medium, H2SO4 (View full solution)
Category: Chemistry
How many equivalents of hydroxide ion are needed to react with 1.53 equivalents of hydrogen ion? How did you know this when no balanced chemical equation was provided for the reaction?
Coursepivot December 14, 2022 17:03
Explanation Explanation: step: 1 of 3 One equivalent is the amount of acid that furnishes 1 mole of hydrogen ions. One equivalent is the amount of base that furnishes 1 (View full solution)
Category: Chemistry
When aqueous solutions of lead(II) ion are treated with potassium chromate solution, a bright yellow precipitate of lead(II) chromate, \mathrm{PbCrO}_{4}PbCrO4​, forms. How many grams of lead chromate form when a 1.00-\mathrm{g}1.00−g sample of \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}Pb(NO3​)2​ i...
Coursepivot December 14, 2022 17:02
Explanation Overall equation K2CrO4 +Pb(NO3)2 =PbCrO4+2KNO3 Mole ratio of Pb(NO3)2 to K2CrO4=1:1 moles of 1.00g Pb(NO3)2 = grams/molar mass of Pb(NO3)2 =1/331.2=0.003 moles Moles of 25mL, 1M K2CrO4= 1 mole*1000mL/25 (View full solution)
Category: Chemistry
A sample of sodium hydrogen carbonate solid weighing 0.1015 g requires 47.21 mL of a hydrochloric acid solution to react completely. Calculate the molarity of the hydrochloric acid solution.
Coursepivot December 14, 2022 17:02
Explanation Number of moles of sodium hydrogen carbonate (NaHCO3 ) reacted = Amount of sample/ Molar Mass of NaHCO3 Molar Mass of NaHCO3=84 g Number of moles of sodium hydrogen (View full solution)
Category: Chemistry
How much water must be added to 500. mL of 0.200 M HCl to produce a 0.150 M solution? (Assume that the volumes are additive.)
Coursepivot December 14, 2022 17:01
Explanation 1.- This is a dilution exercise, where the moles of the solute remain constant throughout the process: ninitial = Cinitial * Vinitial nfinal = Cfinal * Vfinal Like: ninitial (View full solution)
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